Captain Brann
Mongoose
Hi Barrages make no sense at all.
if you have more than 12 points of armor on a ship you will never take damage as you subtract 12+ from your to hit roll which will not let any damage through.
A large bay Particle beam can do 9d6 dam which is an average of 31dam, if you have 15 armor 16 dam would get past. Under the barrage system it is unlikely any would even though you will be firing many bays at once.
Can anyone explain this to me??
It seems to me that the armor should be taken from the average damage for a weapon before you multiply by the number firing and then that damage is changed by the damage chart based on the other defenses in play. If you start with a zero or below damage number then count it as 1/4 for the purposes of working out the damage effect [per 10 weapons firing]. this will turn the Barrage damage chart from Dice damage to actual damage.
For example in the above with 10 large bay Particle beam's can do 9d6 dam which is an average of 31dam, if you have 15 armor 16 dam would get past. Which works out as 160 damage if the firing ship scores a 12 to hit you would score 225% 385 damage to the target.
Using the books example the missiles would be average damage 7 less the 2 amour makes 5 damage. The defense reduces the attack roll of 12 by 4 for the screens, 1 for the lasers, 0 for the sand = 5. SO the attack roll becomes 7 200 missiles x average 5 damage = 1000 damage x 100% = 1,000 damage on the Victory.
If the Victory had armor 4 the damage would end up as 3 x 200x 100% = 600.
If the Victory had armor 6 the damage would be 1 x 200 x100% = 200.
If the victory had armor 7+ then the damage would be 1/4 x 200 x 100% = 50.
This seems to make more sense to me than the original, however I might just be totally missing the point of the original.
Chris
if you have more than 12 points of armor on a ship you will never take damage as you subtract 12+ from your to hit roll which will not let any damage through.
A large bay Particle beam can do 9d6 dam which is an average of 31dam, if you have 15 armor 16 dam would get past. Under the barrage system it is unlikely any would even though you will be firing many bays at once.
Can anyone explain this to me??
It seems to me that the armor should be taken from the average damage for a weapon before you multiply by the number firing and then that damage is changed by the damage chart based on the other defenses in play. If you start with a zero or below damage number then count it as 1/4 for the purposes of working out the damage effect [per 10 weapons firing]. this will turn the Barrage damage chart from Dice damage to actual damage.
For example in the above with 10 large bay Particle beam's can do 9d6 dam which is an average of 31dam, if you have 15 armor 16 dam would get past. Which works out as 160 damage if the firing ship scores a 12 to hit you would score 225% 385 damage to the target.
Using the books example the missiles would be average damage 7 less the 2 amour makes 5 damage. The defense reduces the attack roll of 12 by 4 for the screens, 1 for the lasers, 0 for the sand = 5. SO the attack roll becomes 7 200 missiles x average 5 damage = 1000 damage x 100% = 1,000 damage on the Victory.
If the Victory had armor 4 the damage would end up as 3 x 200x 100% = 600.
If the Victory had armor 6 the damage would be 1 x 200 x100% = 200.
If the victory had armor 7+ then the damage would be 1/4 x 200 x 100% = 50.
This seems to make more sense to me than the original, however I might just be totally missing the point of the original.
Chris