Yes, probably. Or it depends. The gravity is likely to be very extreme, though. If you have something the size of Jupiter with 13-70+ times the mass of Jupiter, the gravity will be very high. Luckily the cooler ones tend to be smaller (or older). Since we're not 100% clear in explaining how m-drive works and whether the ship also has lifters to counteract gravity (they would have to, to refuel at Jupiter without M-3 or better drives), then it's a big 'it depends'.
Another 'it depends'. The way the orbits are described (for backward compatibility and sanity's sake and to allow any of this to run without a computer) they're centered on the biggest (Primary) star. So, as they get written down, the orbit of a star or planet outside the orbit of a Close, Near or Far star 'looks' like it is orbiting the Primary star (and companion, if present), but if you looked at it from a barycenter view, it would be orbiting all of the stars inside its orbit.
For the purpose of the sentence and the table entry, any star inside that orbit number would be something to count. Theoretically, it could be as many as six.