simonh said:
There's a major problem with the counter-ring concept.
The ring itself, and also any counter-ring, is not in orbit around the star. The net gravitational attraction to the star of any homogenous ring (or sphere) around it is zero, which means there is no net gravitational force keeping the ring centered on the star. Any lateral force on the ring will tend to cause it to drift so the star is off-center and unless counteracted would cause the ring to eventually touch the star.
In Ringworld Engineers Larry described a series of fusion ramjets along both edges of the ring, scooping up hydrogen from the solar wind, compressing and fusing it and using the resultant thrust to stabilize the ring. If you also have a counter-ring of matter 338 times the mass of the ring itself, you'll need a stabilization system for it with 338 times the thrust. If anything ever goes wrong with that system, or with the (magnetic?) mechanism coupling the counter-ring with the inner one, both are toast.
Furthermore, if you couple the counter-ring to the inner one magnetically, those magnetic fields are going to have to be staggeringly powerful, in fact probably powerful enough to tear the ring apart. Without a super-science material insulating the inside of the ring from those fields, any electronic, or even just ferrous metallic material in the ring interior is going to get induced currents and be exposed to magnetic forces that will blast them electrically while simultaneously throwing them around like tissue paper in a hurricane.
Simon Hibbs
Superconductor
Magnet
Superconductor
Magnetic fields repel superconductors and superconductors also block magnetic fields.
The way it works is that a magnetic field induces an electric current in a superconductor which produces the opposite polarity magnetic field. If there is a superconductor between yourself and the magnetic field, the opposite polarity magnetic field produced by the superconductor cancels out the first one, thereby shielding you from the effects of the magnetic field.
I did mention there was a superconductor layer underneath the bonded bedrock and dirt and loose rock, that superconducting layer, even if not scrith, will shield you from the magnetic fields required to repel the ring off of the counter ring. This superconducting layer can also be used to levitate the maglev vehicles described by Larry Niven. So the superconducting layer under the bedrock does double duty, one as a shield against the intense magnetic fields and secondly as a giant maglev track for flying vehicles operating within the ringworld environment. As for the instability of the ringworld, yes I know about it, that is why the ringworld is not an abandoned structure or relic, it is more like a living object, it maintains itself including stabilize itself when it drifts off center. The same mechanism which stabilizes the ring can also stabilize the outer ring as the ring pushes on the outer ring through its interaction with it using magnetic fields. This ringworld, were talking about is 1.25 AU in radius by the way, to be in Alpha Centauri A's habitable zone, and the ring takes 10 days to make a complete rotation. The mass of the ring is correspondingly 1.25 times Jupiter's mass. In kilometers it is 187,500,000 km in radius with a circumference of 1,178,097,245 km. Each subsector hex is 20,000 km across, a subsector is 10 hexes north and south and 8 hexes across. therefore it is 200,000 km north to south and I have previously determined each one to be 138,365.38 km east to west by drawing a subsector with regular hexes and counting the pixels across. Dividing the circumference by the width of a subsector we get a ringworld that is 8,514.39 subsectors. A sector is 4 subsectors across so there are 2,128.60 sectors in circumference, we can fudge it and make it exactly 2,129 sectors in circumference by increasing the radius of the ringworld by a tiny amount, it stays effectively the same as far as the ringworld inhabitants can tell. The ringworld band is also 2 sectors across as a subsector is 200,000 km north to south, 4 of those is 800,000, and 2 sectors is 1,600,000 km across. From this we can tell how many 20,000 km wide hexes there are. A sector is 32 hexes east to west 32 hexes times 2,129 sectors equals 68,128 hexes in circumference, since each sector is 40 hexes north to south and the ring world is two sectors wide that 80 hexes across, so 80 times 68,128 hexes equals 5,450,240 hexes over the entire ringworld surface.
The Earth's surface area is 510,072,000 sq km, the surface area of a 20,000 km wide hex is 6 times the surface area of an equilateral triangle that is 15,000 km on a side, the area of a triangle is one half height times base, the height is 10,000 km, half the base is 7,500 km, so 7,500 times 10,000 equals 75,000,000 square km times 6 equals 450,000,000 sq. km which is 0.8822 times the Earth's surface per hex thus with 5,450,240 hexes we have 4,808,356.47 times the Earth's surface area.