Hello AnotherDilbert,
Thank you for your help and I appear to be having a comprehension problem and or trying to eccentrically interpret the rules. I will try another route to see if I can get on the right track.
AnotherDilbert said:
snrdg121408 said:
The International Space Station, the space shuttle and the space capsules are in my understanding "non-gravity hulls." Using artificial gravity plates, double hulls, or hamster cages generate a gravity field. A planetoid or buffered planetoid are "non-gravity hulls."
How do I calculate the d-tons and cost of adding grav plates to planetoid or buffered planetoid?
Can planetoid or buffered planetoid hulls use hamster cage or double hulls?
Planetoids are a configuration (hull shape) for hulls. They are not "non-gravity hulls" by default.
msprange said:
Assume planetoids do come with gravity hulls (assumption for all hulls unless you deliberately decide otherwise).
There is no defined cost for a Non-gravity planetoid hull (and the grav plates are remarkably cheap on planetoids).
The first step is to decide the amount of space or volume that will be enclosed by the structure being built. I've decided the volume will be 1,000 displacement tons (d-tons). There are two way to enclose a space with a volume of 1,000 d-tons. The first way was to build a frame that contains a volume of 1,000 d-tons. The second option is to take a rock from an asteroid/planetoid belt and tunnel out the required volume of 1,000 d-tons.
To build a structure or hull that has a volume of 1,000 d-tons cost Cr50,000 per d-ton and appears to include grav plates as part of the construction process. The cost of the basic hull is Cr50,000,000.
Using a rock from the planetoid/asteroid belt requires selecting the right size that will have enough material to allow the creations of a space that has a volume 1,000 d-tons. Once the right size rock has been selected it is towed to the shipyard where the tunneling is done to create the space to house a volume of 1,000 d tons at a cost of Cr4,000 per d-ton of rock.
The next step is to decided the configuration of the hull. There are five configurations to select from for hulls that are built to enclose a space with a volume of 1,000 d-tons. The configurations are standard, streamlined, sphere, close structure, and dispersed structure. The four of the configuration options increase or decrease the cost of the hull.
A rock taken from an asteroid/planetoid belt have two configurations which are planetoid and buffered planetoid. A planetoid hull configuration can only tunnel out 80% of the interior which means that to get a space with a volume of 1,000 d-tons my rock has to start with an unmodified volume of 1,250 d-tons with a cost of Cr5,000,000. A buffered planetoid can only remove 65% of its interior requiring the selection of a rock with a starting volume of approximately 1,538.462 d-tons and costs Cr6,153,848.
A hull with a volume of 1,000 d-tons using either standard, streamlined, sphere, close structure, or dispersed structure can be built without grav plates, referred to as non-gravity, for Cr25,000 per ton. The 1,000 d-ton without grav plates has a cost of Cr25,000,000.
A rock configured as a planetoid or buffered planetoid hull per Matthew Sprange assumes that they have grav plates and indicates that they are included as part of the Cr4,000. Which appears support "There is no defined cost for a Non-gravity planetoid hull (and the grav plates are remarkably cheap on planetoids)."
Based on the rule for the non-gravity hulls, if I am remotely close in my understanding to the rule, my guess is that the cost of a planetoid or buffered planetoid hull should total hull d-tons times Cr2,000.
According to the rules there are two alternate ways to create a 1G field on a hull instead of using grav plates. If I am following the rules the Cr50,000 per d-ton is for a hull configuration of standard, streamlined, close structure, or dispersed structure with grav plates.
Does installing a double hull or hamster cage to generate a 1G field add to the Cr50,000?
If not, how is the base cost of the hull determined?
I'm hoping that my comprehension and interpretation of the rules is in line with what they are saying.