I'm a bit confused about how to calculate the drive and power plant volumes in ships - here's how I think it works if I'm reading it right:
Say I had a 500 dton ship. If I wanted to add J5 to it, I'd need a type N Jump Drive, right? Or a type P, though I'm not sure why I'd want that because it's bigger and more expensive and uses more fuel for no gain in jump.
And because I have a type N jump drive, I'd need at least a type N power plant too, right?
And if I wanted to give it a 4G Manoeuvre drive, it'd need a type K, right (again, why would I bother with the L and M options that are available)?
So in total, that's 70 + 19 + 40 = 129 dtons used for the J-drive, powerplant, and M-Drive respectively, costing a total of 130 + 40 + 104 = 274 MCr.
Being a type N, the powerplant would need 26 dtons of fuel to run the ship for two weeks, and I'd need 250 dtons of fuel for a single J5 jump (0.1 * 500 * 5).
Is that right?
And would a smaller jump use less fuel? (i.e. would a J2 jump use up 100 dtons of fuel instead of 250?).
Say I had a 500 dton ship. If I wanted to add J5 to it, I'd need a type N Jump Drive, right? Or a type P, though I'm not sure why I'd want that because it's bigger and more expensive and uses more fuel for no gain in jump.
And because I have a type N jump drive, I'd need at least a type N power plant too, right?
And if I wanted to give it a 4G Manoeuvre drive, it'd need a type K, right (again, why would I bother with the L and M options that are available)?
So in total, that's 70 + 19 + 40 = 129 dtons used for the J-drive, powerplant, and M-Drive respectively, costing a total of 130 + 40 + 104 = 274 MCr.
Being a type N, the powerplant would need 26 dtons of fuel to run the ship for two weeks, and I'd need 250 dtons of fuel for a single J5 jump (0.1 * 500 * 5).
Is that right?
And would a smaller jump use less fuel? (i.e. would a J2 jump use up 100 dtons of fuel instead of 250?).