I don't know. I just made an odd guess from the deckplans.
On a deckplan, a torpedo is 5 squares by 1.5.
A square is 1.5 by 1.5
5x1.5=7.5
so I reduced that slightly to add loading systems and cradles and stuff.
Gives me 7.4x1.2 or so
No fancy calcs, just a bit of good guessing
Now: vol=pi x r squared x h
is: h= vol/ pi x r squared
is: h= 35/ pi x 0.5625
is: h= 35/ 1.7671 (and lots more figures)
is: h= 19 metres....
hmmm... your math looks about right, I think your cubic volume is off...
lets see...volume should in fact be
7.5x1.5x3=33.75.... buggery...
I think my maths is bad too. I'm not sure how, but it is. Wait! half that volume, because a ton is 3 metres tall, while the torpedo is only 1.5 metres tall... so volume should be:
7.5x1.5x1.5=16.875
So:
H= 16.875/1.7671
H= 9 metres long.
Still a little off, but much closer.
Lets do it the other way:
volume= pi x 0.5625 x 7.5
volume = 13.253
There you go. Volume of a torpedo is it is 7.5 metres long and 1.5 metres in diameter.
Ouch... I have done too much maths today... and I'm a history student
