A
Anonymous
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@phavoc
Your physics is wrong.
"But I pasted it from NASA"
Yes but you pasted an article that doesn't describe in full how lift works. It's correct but incomplete for reasons of length.
You have many forces on a wing that provide lift. A partial list is:
(1) the pressure diferential above the wing "sucking" the aircraft up - caused by airfoil shape, and by tilting the wing upwards.
(2) Netwon's 3rd law. tilting the wing upwards meaning air being deflected downwards and creating an upward reaction.
If you admit there is air deflected downwards, you must also realise there is an upward reaction force exerted? This is how a helicopter rotor works, right? There's basically no difference between wing and rotor physics. Both are shaped, angled surfaces that are moved through air, generating an upward force by the same mechanisms. If you were to turn one wing of a plane upside down and spin the plane on a turntable, you would have a rotor blade.
In the case of a brick, (2) i think is more significant as it's a stupid shape for flying.
As for the airframe drag: If the m-drive needs more thrust in atmosphere to cancel out the increased drag, why can't it generate the same thrust in space, and therefore provide higher acceleration in vacuum? We have to pick one of "game approximatation" or "negligible drag on hull"
Your physics is wrong.
"But I pasted it from NASA"
Yes but you pasted an article that doesn't describe in full how lift works. It's correct but incomplete for reasons of length.
You have many forces on a wing that provide lift. A partial list is:
(1) the pressure diferential above the wing "sucking" the aircraft up - caused by airfoil shape, and by tilting the wing upwards.
(2) Netwon's 3rd law. tilting the wing upwards meaning air being deflected downwards and creating an upward reaction.
If you admit there is air deflected downwards, you must also realise there is an upward reaction force exerted? This is how a helicopter rotor works, right? There's basically no difference between wing and rotor physics. Both are shaped, angled surfaces that are moved through air, generating an upward force by the same mechanisms. If you were to turn one wing of a plane upside down and spin the plane on a turntable, you would have a rotor blade.
In the case of a brick, (2) i think is more significant as it's a stupid shape for flying.
As for the airframe drag: If the m-drive needs more thrust in atmosphere to cancel out the increased drag, why can't it generate the same thrust in space, and therefore provide higher acceleration in vacuum? We have to pick one of "game approximatation" or "negligible drag on hull"
phavoc said:Moppy said:Obviously the brick is powered. Since it's sufficiently powered and tilted up at the front, it generates lift by deflecting air downwards. It will also tumble to chaotic forces and then lose lift. Maintaining the precise angle to generate lift is problem of control. I have absolutely no idea why you think the air cannot generate enough force to provide sufificient lift, as wind storms like tornados can easily lift bricks.
Drag from parachutes don't matter. The maneuver drive ignores it. It generates the same acceleration in vacuum and in atmopshere, right? Therefore there is almst zero drag on a ship powered by that engine. Although as I said, there i obviously some limit. Parachutes will flap about and cause minute attitude shifts, hence it's a control problem to maintain your angle. The reduction of drag also means less lift, which is problematic. There's still the bernoulli effect
I don't claim those planes are identical to a Type-R. Just that saying the wings of a Type-R are too fat is unsupportable. None of us knows if the Type-R shape is possible under Traveller physics. Another thing to consider for Traveller ships are waveriders and ground effect.
Umm, in my example the brick was being held by a hand in a car at 50mph. And it was an unpowered brick. Most bricks, I think, would fall within that category. As I mentioned previously (original data can be found here - https://www.researchgate.net/publication/276294924_Martin_X-24A_Lifting_Body) the lift-to-drag ratio of a brick is 0 with a glide angle of 90 degrees. The glide angle for a lifting body is 16 degrees, the space shuttle is 12 degrees. A tumbling brick wouldn't have one since it's tumbling (well, technically, it would have more than one, as it would run through a whole bunch as it tumbled, but effectively it would have none).
As has been continually cited, yes, the brick CAN generate lift - but ONLY when the forward velocity is sufficient to overcome both mass and drag. And it doesn't generate lift by deflecting air downwards, lift is generated by air pressure being different above and below couple with the speed of the air. If air is moving faster above than below then no lift can be generated. The space shuttle and the X-series lifting bodies also would adjust their angle of attack. Again, going back to the boys from NASA, click on the link here - https://www.nasa.gov/centers/johnson/pdf/584730main_Wings-ch4d-pgs226-241.pdf - refer to page 12. You will see how the shuttle angles it's nose to take advantage of drag during the deorbiting. The X-series craft, also designed to be fly from orbit, do the same. The lift is there to offset their 'brick' status and to allow for the craft to travel farther, thus giving them more landing sites. The NASA article also gives a lot of information regarding pressure and other issues that spacecraft have to deal with deorbiting. Which is another reason why using anti-gravity is a wonderful thing - less stress, less heat, less everything when entering the atmosphere. You can essentially 'sink' to your landing spot, though air turbulence and such would probably require some powered flight in order to have more control and speed.
As to your tornado question, that's simple. Tornadoes create vortexes. They also create pressure differentials. Air pressure is something aircraft also deal with to generate lift. High pressure on the ground and lower pressure in the tornado, combined with the vortex, create lift. A tornado is very destructive thing with a helluva lot power in it. Things far heavier than a brick get picked up. I've never said air cannot generate enough force to provide lift. Please go back and re-read what I have said (and what I have quoted and cited). You will find that to be an incorrect statement.
Why do you think drag does not matter? Even if you don't want to listen to me it doesn't make your assumption wrong. Drag is a force just like lift. You can disbelieve me all day long but that won't change the science. It's not me, personally, saying that by the way.
M-drive does not ignore drag. NOTHING flying ignores drag unless there is a field surrounding the object that ignores fluid dynamics. An M-drive may be able to generate the same THRUST in both atmosphere and vacuum - however vaccum has zero drag and atmosphere has infinitely more. The greater the density the more drag there is and the more thrust you must apply to maintain your current flight envelope. Again you need not believe me personally. Do just a teeny-tiny amount of investigations and you will find this to be a true statement.
I agree that none of us know the true shape of the wing. But the illustrations provided, along with the obvious characteristics from the illustrations and how they differ so greatly from the ones you provided allow us to have an inference. While you may not want it to be true, you cannot deny how aerodynamics work. And even a cursory review of the field will support my point. I'm having a problem embedding images, but you can see from the drag curve diagram that as velocity increases so does drag - https://en.wikipedia.org/wiki/Lift-to-drag_ratio#/media/File:Drag_curves_for_aircraft_in_flight.svg