The actual density of hydrogen as it exist in interstellar space is on the average of about 1 atom per cubic centimeter. So how many cubic centimeters in a comet that has a volume of one cubic km? There are 100,000 cm in a km so a km^3 = 1,000,000,000,000,000 atoms in a cubic km of space, now how much mass is this? One mole of hydrogen is 2 kg which is 2 times avagodro's number of atoms and avagodro's number = 6.02214179*10^23 atoms of hydrogen in 1 kg. So the number of hydrogen atoms in a cubic km of space has the mass of 1.6605387831627258978902255305417*10^-9 kg. So plug this number into E=MC^2 and we get
149,448,490 joules of energy, or actually twice that which is 298,896,981 joules of energy. Lets say the comet is moving relative to the hydrogen atoms at 1 km/sec that means every time it moves into a new cubic kilometer of space it is colliding with 1,000,000,000,000,000 atoms of hydrogen, this releases 300 megajoules of energy or generates 300 megawatts of power in the form of gamma rays by definition. So you think an antimatter comet that is radiating 300 megawatts of gamma rays ought to be detectible by the Regina authorities? How does that compare with the radiation of the Sun. The Earth receives about 1400 watts per square meter, now if the comet was in the shape of a cube, it would have a surface area of 6,000,000 square meters, this comes to about 50 watts per square meter of the comet, so it basically has the same output as a 50 watt light bulb over its entire surface, but the wattage is in gamma rays so it would be quite invisible to human eyes.