GypsyComet said:
Not everyone who plays this game wants to whip out the calculator or has the education to know that "simple formula".
They don't need any education. The formula would be provided with the table, and the GM would calculate it as needed. Most of the time he can even do it in his head on the fly, as I will now demonstrate:
As an example of how this doesn't have to be hard, the actual "rocket science" formula to calculate travel time for standard constant acceleration-turnover-constant deceleration is
t = SQRT(2s/a) (where t= time to midpoint in seconds, s = midpoint distance in metres, and a = acceleration in m/s²)... that's too complicated for use in a game, but it doesn't need to be at all. We can simplify this a lot because we're not going to have our units in metres or seconds or m/s² - we're going to have them in AU and days and Gs.
If you change the time units to days, the distance units to AU, the acceleration to Gs (1G = 10 m/s²), and then figure it out to get the TOTAL travel time in days, then what you end up with is this:
TOTAL Travel time in days = 2.835 * SQRT(s/a) where s is TOTAL distance in AU and a is in earth gravities.
So, a ship travelling a total of 10 AU and accelerating at 2g to the midpoint and then turning over and decelerating at 2g to its destination would take just over 6 days to get there. If you have a calculator to hand it takes less than 10 seconds to use it to figure that out, and the game is in no way disrupted.
But, you may argue that even that is fiddly. So here's another way:
TOTAL Travel time in days = 4 * SQRT(s/a) where s is MIDPOINT distance in AU and a is in earth gravities.
You could do that in your head for many cases. That's it - it's that simple.
Try it: How long does it take for a ship to travel 60 AU if it's using the standard accelerate-turnaround-decelerate method with an acceleration of 4G?
Just doing it in my head using the second equation (remembering to use the MIDPOINT distance of 30AU), I figure about 10 or 11 days. The actual answer is 10.98 days. It's not hard to do if you have any numerical literacy at all (it took me about 10 seconds to do that in my head).
Now try this one: How long does it take for a ship to travel 2 AU if it's using the standard accelerate-turnaround-decelerate method with an acceleration of 1G? (this one is REALLY easy, I'll let you figure it out).
Besides which, travel time tables are largely useless anyway. They'll give you travel times assuming that the planets never move in their orbits, but of course that never happens - sometimes planets are on the other side of their orbits relative to another one. The SIMPLE calculations I have provided here (I know you won't thank me for the effort) will let you figure out on the fly how long it takes to get from A to B.
I suppose that you'll still come up with an excuse not to use them though, but hopefully someone else may find them useful. :roll:
If it becomes established that ships can skim from brown dwarf stars, then I'll stop worrying about diving into a jovian with a hundred times the solar input of Jupiter. Or a thousand times.
It's already established that they can't skim brown dwarfs - the gravity is way too high on those (10s to 100s of g). And you don't need to skim the hottest gas giant hugging the star's corona on a torch orbit, there would probably be others further out in the more normal inner zone that would only have surface temperatures of a few hundred degrees that would be perfectly usable.