AnotherDilbert
Emperor Mongoose
Reynard said:"The jump drive is powered by the battery, which is recharged during the normal refuelling operations."
So that means any ship with enough HEBs can also charge the jump that way.
Agreed, a jump drive only needs energy, but wast amounts. In a fusion economy it needs both a bit of energy and a lot of fuel (to be turned into energy).
Only antimatter power or other exotic power systems can provide the needed energy without large amounts of fuel.
Let's estimate:
Take a 1000 Dton ship with J-1 at TL-12. It needs a 20 Dt power plant producing 300 Power to power basic systems (200 Power) and either the M-drive or the J-drive (100 Power). It uses 2 Dt fuel over 4 weeks, or 1 Dt per two weeks.
In two weeks the PP would produce 300 Power for 2 × 7 × 24 × 10 = 3360 turns or about 1 000 000 PowerTurns = 1 MPowerTurn from 1 Dt fuel.
A J-1 would require 100 Dton fuel or about 100 MPowerTurn energy.
One Dt of HiEfficiency Batteries holds enough energy to produce 60 Power for 1 turn so 60 × 1 = 60 PowerTurns/Dt.
100 MPowerTurns required / 60 PowerTurns/Dt ≈ 1.7 million Dt batteries required.
So roughly a 1 000 Dt ship would require 1 000 000 Dt batteries to power a jump-1. Obviously that is not happening...
Estimate Two:
At very roughly 1 Power = 10 MW, 100 MPowerTurn (one jump) would be 100 000 000 PowerTurn × 10 [MW/PowerTurn] / 10 [turns/hour] = 100 000 000 MWh = 100 TWh = 100 billion kWh.
That is roughly what ten nuclear reactors of 1000 MWe each produces in a year. Or twenty Hoover dams. Or about 100 large wind power parks with a total of tens of thousands wind mills covering 7800 km² (≈Delaware) (Shepherds Flat Wind Farm).
For one jump...