Striking a target at distance in space:
Speed of light c, approx 300,000,000 m/s, or 300,000 km/h. Assuming a light speed weapon and sufficiently advanced turrets, sensors and computers:
Sensor ping to identify target at a distance (light speed).
Return sensor data confirming target distance/velocity/etc (light speed).
Some-sort-of-calculation (? time)
Aiming the beam weapon (? time)
Firing the beam weapon (light speed).
At very long range (50,000 km): Each light-speed traversal is 0.167 seconds, meaning a minimum of 0.5 seconds (half a second) assuming negligible calculation/weapon aiming time (perhaps this happening in the 0.333 seconds that the sensor ping is being sent and received)
At long range (25,000 km): 0.25 seconds - obviously half the above.
Obviously the above numbers are heavily skewed (that it takes zero time to calculate and aim a weapon at a target..).
Anyways the my question is regarding the calculation of the displacement of the target in that 0.5 seconds and 0.25 seconds. Assume 6g and 10g acceleration... is it simply:
6g = up to 14.7 and 4.3625 meters displaced?
10g = up to 24.5 and 6.125 meters displaced
Speed of light c, approx 300,000,000 m/s, or 300,000 km/h. Assuming a light speed weapon and sufficiently advanced turrets, sensors and computers:
Sensor ping to identify target at a distance (light speed).
Return sensor data confirming target distance/velocity/etc (light speed).
Some-sort-of-calculation (? time)
Aiming the beam weapon (? time)
Firing the beam weapon (light speed).
At very long range (50,000 km): Each light-speed traversal is 0.167 seconds, meaning a minimum of 0.5 seconds (half a second) assuming negligible calculation/weapon aiming time (perhaps this happening in the 0.333 seconds that the sensor ping is being sent and received)
At long range (25,000 km): 0.25 seconds - obviously half the above.
Obviously the above numbers are heavily skewed (that it takes zero time to calculate and aim a weapon at a target..).
Anyways the my question is regarding the calculation of the displacement of the target in that 0.5 seconds and 0.25 seconds. Assume 6g and 10g acceleration... is it simply:
6g = up to 14.7 and 4.3625 meters displaced?
10g = up to 24.5 and 6.125 meters displaced