Shields Question

snubby

Mongoose
Ok it says that for evrypoint shields take one hit, for beam weapons does this mean each 4+ that hits or for each starting AD that hits?

Example 1.
Beem attacks first roll is 6AD one gets 2, 3, 4, 4, 5,6
So since its shields four hits are removed and your done (with double dmg adding up or triple)

Example 2
Beem attacks with 6Ad gets teh 2, 3, 4, 4, 5, 6 then rolls the 4-6 again and gets say 1, 1, 4, 6 and then rolls the 4 and 6 again and get both 2 so that would end up with 6 hits on shields
 
Your second example would be correct.
Essentially a hit is any attack dice that equals the target score. For a beam, it could be considered to have "conditional" attack dice, that only get rolled if triggered by the previous roll, if that makes sense
This also applies for dodge, so if dodging the example you gave, you'd have to make 6 dodge rolls
 
I am not sure I am reading this right.

I will give my own example and tell me if this is right

A ship has 5 shields

its gets hit with 5 AD of DD beam, the shields will stop three of those due the the DD, the other two get through and criticals can be rolled on those correct?
 
I believe that's correct; the first 2 hits damage 4 points of shields, but there's still one point of shield remaining to block the 3rd. the damage that doesn't carryover from that hit though, so the remianing 2 hits roll locations (BH, solid, or solid+crit)

Chern
 
Marco Raimeous said:
its gets hit with 5 AD of DD beam, the shields will stop three of those due the the DD, the other two get through and criticals can be rolled on those correct?
You have it right, assuming you mean it takes 5 hits; it has nothing to do with the starting AD. Its just based on the total number of hits inflicted.
 
Thanks for the reply's, kinda hate trying to reget back into a game when things have changed so much, yet so little. :)
 
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